Quality Control Management

Download Inspection Errors for Attributes in Quality Control by Norman L. Johnson PDF

By Norman L. Johnson

This publication offers a entire survey of the latest methodology--both theoretical and applied--on the statistical research and detection of defective/"non-conforming" goods in quite a few varieties of inspection for attributes, while the inspection itself is topic to blunders.

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For D = 5: P(A) = 0·5221 + 0·3689 = 0'8910; for D = 20: P(A) = 0·0620 + 0·2027 = 0·2647. case (c): p = 0·8 and p' = 0·025. For D = 5: P(A) = 0·3587 + 0·3960 = 0'7547; for D = 20: P(A) = 0·0433 + 0·1606 = 0·2039. e. 75, N= 100, 0 = 20, n = 5 Pr[Z=z] 1 . 00, N= 100, 0=20, n=5 Pr[Z=z] 1 . 5 ......... .. 05, n = 5 Pr[Z=z] 1 . 025 . 0t---------r--____ 0 . 5 : 1 - - - - - - - 1.......... 025 (d) ........ 2 The distribution of the number of items z classified as noncOliforming when there is imperfect inspection - the finite lot size case BASIC DISTRIBUTIONS: SINGLE SAMPLING 26 since 0·2039 > 0·1453.

Conclusion From the analytic expression for acceptance probability, it is hard to see the direction of the influence caused by the effects of varying parameters such as p, p', N, nand D. However the computation results provide quite a clear picture. 01. Second, (or double sampling schemes, when the sample size is large, the effects of changes in p and p' are more significant, but the lot size has little effect on the probabilities of acceptance for given DIN. Finally, for link sampling procedures, the probabilities of acceptance are naturally sensitive to differences between D; and the average of D; _ 1 and Di+ l' All of the above features of these schemes are intuitively reasonable, but they serve as reminders of the delicate relationships among the parameters and sensitivity to values of the error probabilities.

For the jth sample, we assume the probability of correctly (incorrectly) declaring an NC (C) item as NC on inspection is Pj (pj) for j = 1, ... ,k. We will study the distribution of the numbers Z == (Z 1, ... , Zk) of items declared NC after inspection. As before, we will also obtain expressions for relevant moments. 3. 2 The case of equal error probabilities Here we assume the error probabilities are the same for all samples, so that P = Pl ... = Pk and p' = p~ ... = p~. Distributions Let Y == (Y 1 , ...

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