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By Evans L., Thompson R.

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In the diagram below, the points on opposite edges are equivalent in pairs in the indicated directions. As mentioned earlier, the resulting quotient space is homeomorphic to the so-called Klein 33 34 3. QUOTIENT SPACES AND COVERING SPACES bottle. ) An equivalence relation may be specified by giving a partition of the set into pairwise disjoint sets, which are supposed to be the equivalence classes of the relation. One way to do this is to give an onto map f : X → Y and take as equivalence classes the sets f −1 (y) for y ∈ Y .

THE QUOTIENT TOPOLOGY 37 is Hausdorff. ) Here is another simpler description. ) Consider the inclusion i : S n → Rn+1 − {0} and follow this by the projection to RP n . This map is clearly onto. Since S n is compact, and RP n is Hausdorff, it is a quotient map by the proposition above. (It is also a closed map by the proof of the proposition. ) Since S n is compact, it follows that RP n is compact and Hausdorff. Here is an even simpler description. ) Repeat the same reasoning as above to obtain a quotient map of X onto RP n .

Note that the set p−1 (x) (called the fiber at x) is ˜ necessarily a discrete subspace of X. 17. Let X = S 1 , X 1 n ˜ = Rn . map. More generally, let X = (S ) be an n-torus and let X The map E n is a covering map. 18. Let X = S 1 (imbedded in C), and let X n 1 S . Let p(z) = z . This provides an n-fold covering of S by itself. 19. Let X = C, X n p(z) = z . This is not a covering map. Can you see why? What happens if you delete {0}? ˜ = S n and X = RP n . 20. Let X map discussed earlier. This provides a two sheeted covering.

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